Sonata

Sonata performing with scissors

Sonata is a famous singer & superstar. She claims to be one of the five real masters of Big Gallup, and proved her skill by beating Lasso & winning the Big Gallup tournament.

Appearances

Pronunciation Book

Sonata is referred to in 36, which mentions the hotel dreams (several of which she features prominently in). LTAS's gif for 16 depicts Sonata w/Franco at the bar.

@Horse_ebooks

• 16/10/11: "Sonata is the famous"

Bear Stearns Bravo

• Hotel Dreams:
  • 1. 1--Big Gallup Tournie
    2. 2--Sonata plays with scissors

• Solarium Club

Trivia

• Sonata claims that her father invented a certain hand in Big Gallup.
• She toured Sao Paolo in 2005
• Sonata has been seen to perform with scissors as entertainment
• Like Lasso, Sonata has an unusual name; instead, the word "sonata" typically denotes "a composition for one or two instruments, typically in three or four movements in contrasted forms and keys.", as opposed to a person.

Gallery

Sonata's LTAS gif, corresponding to HtP 16. The text reads, "tell the stars you're coming soon".

Sonata (to the left) during the dream sequence of the pirate invasion of the Solarium Club.

Speculation

• LassoxSonata may or may not be canon. In the career science textbook The TruePair Job Matrix, Adventurer & Singerwas listed as a "high-risk" pairing. Not only is Lasso is described as an adventurer & Sonata a a singer, but the book also references other known relationships in such a way (Mark & Sally, PB & Nicole, Henri & Louisa, etc.). Furthermore, they were flirtatious towards each other in the Big Gallup tournament.
  • However, Sonata made Lasso promise to "buzz off for good" if he lost to her, which he did (this rivalry may be what the TruePair book meant by "high-risk").
• Sonata may be German, as when Lady Marquee attempted to beat her at Big Gallup with her "Prussian rubdown", Sonata replied, "if you want to beat a Prussian just invite a German to the table", and laid her hand (it is unknown if she meant the hand was German or herself).